A) 15, 20 and 25
B) 15, 112 and 113
C) 9, 40 and 41
D) 7, 25 and 26
Correct Answer: D
Solution :
In a right angled triangle, square of longest side is equal to sum of squares of other two sides. We will find squares of all given sides and check this condition. A. \[{{15}^{2}}=225,\,{{20}^{2}}\,=400;\,{{25}^{2}}=625\] Clearly \[{{25}^{2}}={{15}^{2}}+{{20}^{2}}\] B. \[{{15}^{2}}=225,\,{{112}^{2}}\,=12544;\,{{113}^{2}}\,=12769\] Clearly \[{{113}^{2}}\,={{15}^{2}}+{{112}^{2}}\] C. \[{{9}^{2}}=81,\,{{40}^{2}}=1600;\,{{41}^{2}}=1681\] Clearly \[{{41}^{2}}={{40}^{2}}+{{9}^{2}}\] D. \[{{7}^{2}}=49,\,{{25}^{2}}=625;\,{{26}^{2}}\,=676\] Clearly \[{{26}^{2}}\ne {{7}^{2}}+{{25}^{2}}\]
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