JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Geometry of complex numbers

  • question_answer
    Let \[{{z}_{1}},{{z}_{2}},{{z}_{3}}\] be three vertices of an equilateral triangle circumscribing the circle \[|z|\]=\[\frac{1}{2}\].  If \[{{z}_{1}}=\frac{1}{2}+\frac{\sqrt{3}\,i}{2}\] and \[{{z}_{1}},{{z}_{2}},{{z}_{3}}\] are in anticlockwise sense then \[{{z}_{2}}\] is [Orissa JEE 2002]

    A) \[1+\sqrt{3}\,i\]

    B) \[1-\sqrt{3}\,i\]

    C) 1

    D) - 1\[\]

    Correct Answer: D

    Solution :

    \[{{z}_{2}}=\,{{z}_{1}}{{e}^{2i\pi /3}}\]\[=\left( \frac{1}{2}+\frac{\sqrt{3}}{2}i \right)\,\,\left( \cos \frac{2\pi }{3}+i\sin \frac{2\pi }{3} \right)\] \[=\left( \frac{1}{2}+\frac{\sqrt{3}}{2}i \right)\] \[\left( \frac{-1}{2}+\frac{\sqrt{3}}{2}i \right)\]\[=-\frac{3}{4}-\frac{1}{4}=-1\].


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