A) \[{{z}_{1}}+{{z}_{4}}={{z}_{2}}+{{z}_{3}}\]
B) \[{{z}_{1}}+{{z}_{3}}={{z}_{2}}+{{z}_{4}}\]
C) \[{{z}_{1}}+{{z}_{2}}={{z}_{3}}+{{z}_{4}}\]
D) None of these
Correct Answer: B
Solution :
Diagonals of a parallelogram \[ABCD\]are bisected each other at a point i.e.\[\frac{{{z}_{1}}+{{z}_{3}}}{2}=\frac{{{z}_{2}}+{{z}_{4}}}{2}\]Þ \[{{z}_{1}}+{{z}_{3}}={{z}_{2}}+{{z}_{4}}\]
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