JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Geometry of complex numbers

  • question_answer
    In the Argand plane, the vector \[z=4-3i\] is turned in the clockwise sense through \[{{180}^{o}}\]and stretched three times. The complex number represented by the new vector is [DCE 2005]

    A) \[12+9i\]

    B) \[12-9i\]

    C) \[-12-9i\]

    D) \[-12+9i\]

    Correct Answer: D

    Solution :

    \[|z|=\sqrt{{{4}^{2}}+{{(-3)}^{2}}}=5\] Let \[{{z}_{1}}\] be the new vector obtained by rotating \[z\] in the clockwise sense through \[{{180}^{o}}\], therefore \[{{z}_{1}}={{e}^{-i\pi }}z=(\cos \pi -i\sin \pi ),\]i.e., \[z=-4+3i\] The unit vector in the direction of \[{{z}_{1}}\]is \[-\frac{4}{5}+\frac{3}{5}i\] . Therefore required vector \[=3|z|\,\left( -\frac{4}{5}+\frac{3}{5}i \right)=15\left( -\frac{4}{5}+\frac{3}{5}i \right)=-12+9i\]


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