A) (2, 0)
B) (\[\sqrt{2},\,\sqrt{2}\])
C) \[(\sqrt{2},\,-\sqrt{2}\])
D) \[(\sqrt{2},0)\]
E) (4, 0)
Correct Answer: D
Solution :
\[z=\sqrt{2}-i\sqrt{2}\] Here, \[\theta ={{\tan }^{-1}}\left( \frac{-\sqrt{2}}{\sqrt{2}} \right)\] = \[{{\tan }^{-1}}(-1)\] = \[{{135}^{o}}\] Now, rotate z in opposite direction with 45° angle \[\therefore \] \[\theta =180{}^\circ \] \[\therefore \] \[\theta ={{\tan }^{-1}}(0)={{\tan }^{-1}}\left( \frac{0}{\sqrt{2}} \right)\] Þ Hence \[x=\sqrt{2}\] and\[y=0\].
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