JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Geometry of complex numbers

  • question_answer
    If \[\omega \] is a complex number satisfying \[\left| \text{ }\omega +\frac{1}{\omega }\text{ } \right|=2\], then maximum distance of \[\omega \]from origin is

    A) \[2+\sqrt{3}\]

    B) \[1+\sqrt{2}\]

    C) \[1+\sqrt{3}\]

    D) None of these

    Correct Answer: B

    Solution :

    Since maximum distance of any complex number \[\omega \] from origin is given by \[|\omega |\] therefore, \[|\omega |\,=\left| \,\omega +\frac{1}{\omega }-\frac{1}{\omega }\, \right|\,\,\le \left| \omega +\frac{1}{\omega } \right|\,+\left| \frac{1}{\omega } \right|=2+\frac{1}{|\omega |}\] Þ \[|\omega {{|}^{2}}-2|\omega |-\,1\le 0\] Þ \[|\omega |\le \frac{2\pm 2\sqrt{2}}{2}\] Hence max \[|\omega |\]is\[1+\sqrt{2}\].


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