A) \[\frac{1}{2\ !}m(m-5)\]
B) \[\frac{1}{2\ !}m(m-1)\]
C) \[\frac{1}{2\ !}m(m-3)\]
D) \[\frac{1}{2\ !}m(m-2)\]
Correct Answer: C
Solution :
Required number of diagonals = \[^{m}{{C}_{2}}-m\] \[=\frac{m\,(m-1)}{2\,!}-m=\frac{m}{2\,!}(m-3)\].
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