JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    If \[S\] is the sum to infinity of a G.P., whose first term is \[a\], then the sum of the first \[n\] terms is [UPSEAT 2002]

    A)   \[S{{\left( 1-\frac{a}{S} \right)}^{n}}\]

    B) \[S\left[ 1-{{\left( 1-\frac{a}{S} \right)}^{n}} \right]\]

    C) \[a\left[ 1-{{\left( 1-\frac{a}{S} \right)}^{n}} \right]\]

    D) None of these

    Correct Answer: B

    Solution :

    Let \[r\] be the common ratio of the G.P. Then \[S=\frac{a}{1-r}\]\[\Rightarrow \]\[r=1-\frac{a}{S}\] Now \[{{S}_{n}}=\] Sum of \[n\] terms \[=a\left( \frac{1-{{r}^{n}}}{1-r} \right)=\frac{a}{1-r}(1-{{r}^{n}})=S\left[ 1-{{\left( 1-\frac{a}{S} \right)}^{n}} \right]\].


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