JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    \[0.\overset{\,\,\,\,\bullet \,\,\,\bullet \,}{\mathop{423}}\,=\]       [Roorkee 1961; IIT 1973]

    A) \[\frac{419}{990}\]

    B) \[\frac{419}{999}\]

    C) \[\frac{417}{990}\]

    D) \[\frac{417}{999}\]

    Correct Answer: A

    Solution :

    We have \[0.\,4\overset{\,\,\,.\,\,\,.\,\,\,}{\mathop{23\,}}\,=0.4232323.......\] \[=0.4+0.023+0.00023+0.0000023+........\infty \] \[=\frac{4}{10}+\frac{23}{{{10}^{3}}}+\frac{23}{{{10}^{5}}}+\frac{23}{{{10}^{7}}}........\infty \] \[=\frac{4}{10}+\frac{23}{{{10}^{3}}}\left[ 1+\frac{1}{{{10}^{2}}}+\frac{1}{{{10}^{4}}}+..........\infty  \right]\] \[=\frac{4}{10}+\frac{23}{1000}\left( \frac{1}{1-\frac{1}{{{10}^{2}}}} \right)=\frac{4}{10}+\frac{23}{990}=\frac{419}{990}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner