A) 1, 3, 9
B) 2, 6, 18
C) 3, 9, 27
D) 2, 4, 8
Correct Answer: B
Solution :
Let numbers are \[\frac{a}{r},\ a,\ ar\] Under conditions, we get \[\frac{a}{r}\ .\ a\ .\ ar=216\]\[\Rightarrow \]\[a=6\] And sum of product pair wise \[=156\] \[\Rightarrow \]\[\frac{a}{r}\ .\ a+\frac{a}{r}\ .\ ar+a\ .\ ar=156\]\[\Rightarrow \]\[r=3\] Hence numbers are 2, 6, 18. Trick: Since \[2\times 6\times 18=216\] (as given) and no other option gives the value.
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