A) \[{{3}^{\frac{2}{n}}}\]
B) \[{{3}^{\frac{n+1}{2}}}\]
C) \[{{3}^{\frac{n}{2}}}\]
D) \[{{3}^{\frac{n-1}{2}}}\]
Correct Answer: B
Solution :
a = 3, r = 3 G.M. = \[{{({{3.3}^{2}}{{.3}^{3}}{{.....3}^{n}})}^{1/n}}\]\[={{({{3}^{1+2+3..........+n}})}^{1/n}}\] \[={{\left( {{3}^{\frac{n(n+1)}{2}}} \right)}^{1/n}}={{3}^{\frac{(n+1)}{2}}}\].
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