JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    Fifth term of a G.P. is 2, then the product of its 9 terms is    [Pb. CET 1990, 94; AIEEE 2002]

    A) 256

    B) 512

    C) 1024

    D) None of these

    Correct Answer: B

    Solution :

    Let the 9 terms of a G.P. is \[\frac{a}{{{r}^{4}}},\frac{a}{{{r}^{3}}},\frac{a}{{{r}^{2}}},\frac{a}{r},a,\]\[ar,a{{r}^{2}},a{{r}^{3}},a{{r}^{4}}\]. Given, fifth term \[a=2\] Hence product of 9 terms is\[{{a}^{9}}={{(2)}^{9}}=512\].


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