A) \[\frac{3}{4}\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{3}\]
D) \[\frac{2}{5}\]
Correct Answer: B
Solution :
\[{{T}_{5}}=a{{r}^{4}}=\frac{1}{3}\] ?..(i) and \[{{T}_{9}}=a{{r}^{8}}=\frac{16}{243}\] ?..(ii) Solving (i) and (ii), we get \[r=\frac{2}{3}\] and \[a=\frac{27}{16}\] Now \[{{4}^{th}}\] term\[=a{{r}^{3}}=\frac{{{3}^{3}}}{{{2}^{4}}}.\frac{{{2}^{3}}}{{{3}^{3}}}=\frac{1}{2}\].
You need to login to perform this action.
You will be redirected in
3 sec
