A) \[^{10}{{C}_{4}}\frac{1}{x}\]
B) \[^{10}{{C}_{5}}\]
C) \[^{10}{{C}_{5}}x\]
D) \[^{10}{{C}_{7}}{{x}^{4}}\]
Correct Answer: B
Solution :
Middle term of\[{{\left( x+\frac{1}{x} \right)}^{10}}\]is\[{{T}_{6}}={{\,}^{10}}{{C}_{5}}\].
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