JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank General term, Coefficient of any power of x, Independent term, Middle term and Greatest term and Greatest coefficient

  • question_answer
    The coefficient of \[\frac{1}{x}\] in the expansion of \[{{(1+x)}^{n}}{{\left( 1+\frac{1}{x} \right)}^{n}}\]is

    A) \[\frac{n!}{(n-1)!(n+1)!}\]

    B) \[\frac{(2n)\,!}{(n-1)!(n+1)!}\]

    C) \[\frac{n!}{(n-1)!(n+1)!}\]

    D) None of these

    Correct Answer: B

    Solution :

    \[{{(1+x)}^{n}}={{\,}^{n}}{{C}_{0}}+{{\,}^{n}}{{C}_{1}}x+{{\,}^{n}}{{C}_{2}}{{x}^{2}}+....+{{\,}^{n}}{{C}_{n}}{{x}^{n}}\] \[{{\left( 1+\frac{1}{x} \right)}^{n}}={{\,}^{n}}{{C}_{0}}+{{\,}^{n}}{{C}_{1}}\frac{1}{x}+{{\,}^{n}}{{C}_{2}}\frac{1}{{{x}^{2}}}+....+{{\,}^{n}}{{C}_{n}}{{\left( \frac{1}{x} \right)}^{n}}\] Obviously, required coefficient of \[\frac{1}{x}\] can be given by \[^{n}{{C}_{0}}{{\,}^{n}}{{C}_{1}}+{{\,}^{n}}{{C}_{1}}{{\,}^{n}}{{C}_{2}}+....+{{\,}^{n}}{{C}_{n-1}}^{n}{{C}_{n}}\]\[=\frac{(2n)!}{(n-1)!(n+1)!}\]


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