A) 1
B) 2
C) 3
D) 5
Correct Answer: B
Solution :
\[C{{H}_{3}}-\underset{normal\,bu\tan e}{\mathop{C{{H}_{2}}-C{{H}_{2}}}}\,-C{{H}_{3}}\]\[C{{H}_{3}}-\underset{\begin{smallmatrix} iso\,bu\tan e \\ (chain\,isomers) \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,}}\,-C{{H}_{3}}\]You need to login to perform this action.
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