A) Fe3+
B) Fe2+
C) Co2+
D) Co3+
Correct Answer: A
Solution :
Fe3+ ® [Ar] 3d6 4s0, number of unpaired electrons = 5 Fe2+ ® [Ar] 3d6 4s0, number of unpaired electrons = 4 Co2+ ® [Ar] 3d7 4s0, number of unpaired electrons = 3 Co3+ ® [Ar] 3d6 4s0, number of unpaired electrons = 4
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