A) Vanadium (Z = 23)
B) Chromium (Z = 24)
C) Iron (Z = 26)
D) Manganese (Z = 25)
Correct Answer: D
Solution :
\[_{25}Mn=3{{d}^{5}}4{{s}^{2}}\] After losing two electron electronic configuration will be like this \[{{(}_{25}}M{{n}^{++}}3d)\] and this is most stable configuration due to half filled orbitals hence third ionization enthalpy will be highest in this case.
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