A) s-block
B) p-block
C) d-block
D) f-block
Correct Answer: D
Solution :
\[Ce-58\] have configuration \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},\] \[4{{s}^{2}}4{{p}^{6}}4{{d}^{10}}4{{f}^{2}},5{{s}^{2}}5{{p}^{6}}5{{d}^{0}},6{{s}^{2}}\] Since, its last electron enter in f- sub-shell, therefore it is a member of f-block.
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