A) 5
B) 4
C) 3
D) 2
Correct Answer: B
Solution :
\[F{{e}^{2+}}\] ion have 4 unpaired electrons \[F{{e}^{2+}}=26-2=24=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}\]
You need to login to perform this action.
You will be redirected in
3 sec
