A) 1
B) \[1\]
C) \[\sin \theta \]
D) \[-\sin \theta \]
Correct Answer: B
Solution :
\[\sin (\pi +\theta )\sin (\pi -\theta )\text{cose}{{\text{c}}^{2}}\theta \]\[=-\sin \theta \sin \theta \frac{1}{{{\sin }^{2}}\theta }=-1\].
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