A) 0
B) \[2\sin 15{}^\circ \]
C) \[\cos 15{}^\circ +\sin 15{}^\circ \]
D) \[\sin 15{}^\circ -\cos 15{}^\circ \]
Correct Answer: A
Solution :
\[\sin 15{}^\circ +\cos 105{}^\circ \] \[\sin 15{}^\circ +\cos (90{}^\circ +15{}^\circ )=\sin 15{}^\circ -\sin 15{}^\circ =0\].
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