A) 3
B) 2
C) 1
D) 0
Correct Answer: D
Solution :
\[\sin {{\theta }_{1}}+\sin {{\theta }_{2}}+\sin {{\theta }_{3}}=3\] \[\Rightarrow \sin {{\theta }_{1}}=\sin {{\theta }_{2}}=\sin {{\theta }_{3}}=1\], \[(\because -1\le \sin x\le 1)\] \[\Rightarrow {{\theta }_{1}}={{\theta }_{2}}={{\theta }_{3}}=\frac{\pi }{2}\Rightarrow \cos {{\theta }_{1}}+\cos {{\theta }_{2}}+\cos {{\theta }_{3}}=0\].
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