A) \[\frac{2p}{{{p}^{2}}-1}\]
B) \[\frac{{{p}^{2}}-1}{2p}\]
C) \[\frac{{{p}^{2}}+1}{2p}\]
D) \[\frac{2p}{{{p}^{2}}+1}\]
Correct Answer: B
Solution :
\[\sec \theta +\tan \theta =p\,\,\Rightarrow \,\sec \,\theta -\tan \theta =\frac{1}{p}\] Subtracting second from first, we get \[2\tan \theta =p-\frac{1}{p}\] \[\Rightarrow \,\tan \theta =\frac{{{p}^{2}}-1}{2p}\].
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