A) m
B) n
C) 2m
D) 2n
Correct Answer: C
Solution :
\[n({{m}^{2}}-1)=(\sec \theta +\text{cosec}\theta ).2\sin \theta \cos \theta \] (\[\because {{m}^{2}}=1+2\sin \theta \cos \theta \]) \[=\frac{\sin \theta +\cos \theta }{\sin \theta .\cos \theta }.2\sin \theta \cos \theta =2m\].
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