• # question_answer What is the sum of the shaded parts of the given figures? A)  $1\frac{2}{3}$B)  $1\frac{1}{4}$C)  $1\frac{3}{4}$D)  $2\frac{1}{4}$

For figure I, Total number of equal parts = 4 Number of shaded parts = 3 $\therefore$ Shaded fraction $=\frac{3}{4}$ For figure II, Total number of equal parts = 16 Number of shaded parts = 8 $\therefore$ Shaded fraction $=\frac{8}{16}=\frac{1}{2}$ So, required sum$=\frac{3}{4}+\frac{1}{2}=\frac{3+2}{4}=\frac{5}{4}=1\frac{1}{4}$