6th Class Mathematics Fractions Question Bank Fractions

  • question_answer What is the value of \[3\frac{1}{12}+\left[ 1\frac{3}{4}+\left\{ 2\frac{1}{2}-\left( 1\frac{1}{2}-\frac{1}{3} \right) \right\} \right]\]?

    A) \[6\frac{1}{2}\]               

    B) \[2\frac{1}{6}\]

    C) \[6\frac{1}{6}\]                 

    D) \[0\]

    Correct Answer: C

    Solution :

    \[3\frac{1}{12}+\left[ 1\frac{3}{4}+\left\{ 2\frac{1}{2}-\left( 1\frac{1}{2}-\frac{1}{3} \right) \right\} \right]\] \[=\frac{37}{12}+\left[ \frac{7}{4}+\left\{ \frac{5}{2}-\left( \frac{3}{2}-\frac{1}{3} \right) \right\} \right]\] \[=\frac{37}{12}+\left[ \frac{7}{4}+\left\{ \frac{5}{2}-\left( \frac{9-2}{6} \right) \right\} \right]\] \[=\frac{37}{12}+\left[ \frac{7}{4}+\left\{ \frac{5}{2}-\frac{7}{6} \right\} \right]\] \[=\frac{37}{12}+\left[ \frac{7}{4}+\left\{ \frac{15-7}{6} \right\} \right]\] \[=\frac{37}{12}+\frac{7}{4}+\frac{8}{6}=\frac{37}{12}+\frac{7}{4}+\frac{4}{3}\] \[=\frac{34+21+16}{12}=\frac{74}{12}=\frac{37}{6}=6\frac{1}{6}\]


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