• # question_answer 5) What is the sum of $\frac{3}{4},\,\,\frac{7}{6}$and$1\frac{3}{5}$ ? A)  $3\frac{2}{3}$                        B)  $\frac{422}{120}$C)  $3\frac{23}{60}$                    D)  $\frac{412}{120}$

(b) To find the sum of $\frac{3}{4}+\frac{7}{6}+1\frac{3}{5},$ find the L.C.M. of the denominators and then add them. L.C.M. of 4, 5 and 6 is 60. Then, $\frac{3}{4}+\frac{7}{6}+\frac{8}{5}=\frac{45+70+96}{60}=\frac{211}{60}=\frac{211\times 2}{60\times 2}=\frac{422}{120}$