A) \[\frac{26}{37}\]
B) \[\frac{6}{37}\]
C) \[\frac{16}{37}\]
D) \[\frac{7}{37}\]
Correct Answer: C
Solution :
(c) Let quantity required to be added be x \[\therefore \,\,x+\frac{21}{37}=1\Rightarrow x=1-\frac{21}{37}=\frac{37-21}{37}=\frac{16}{37}\]
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