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6th Class Mathematics Fractions Question Bank Fractions and Decimals

  • question_answer
    \[\frac{\left( 1-\frac{1}{4} \right)\left( 1-\frac{1}{5} \right)\left( 1-\frac{1}{6} \right)\left( 1+\frac{1}{4} \right)\left( 1+\frac{1}{5} \right)\left( 1+\frac{1}{6} \right)}{\left( 1-\frac{1}{2} \right)\left( 1-\frac{1}{3} \right)\left( 1-\frac{1}{4} \right)\left( 1+\frac{1}{2} \right)\left( 1+\frac{1}{3} \right)\left( 1+\frac{1}{4} \right)}=?\]

    A) \[1\frac{87}{256}\]                               

    B)  \[1\frac{86}{257}\]

    C) \[2\frac{86}{4}\]                       

    D) \[0\]

    Correct Answer: A

    Solution :

    \[\left( \frac{15}{16}\times \frac{24}{25}\times \frac{35}{36} \right)\div \left( \frac{3}{4}\times \frac{9}{8}\times \frac{48}{49} \right)\] \[=\frac{15}{16}\times \frac{24}{25}\times \frac{35}{36}\times \frac{4}{3}\times \frac{9}{8}\times \frac{49}{48}=1\frac{87}{256}\]


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