A) \[\frac{2}{n}\]
B) \[2n\]
C) \[\frac{n+1}{2}\]
D) \[n\]
Correct Answer: C
Solution :
\[\frac{3}{2}\times \frac{4}{3}\times \frac{5}{4}\times \frac{6}{5}........\frac{n+1}{n}\] \[=\frac{n+1}{2}\]
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