A) \[0.5\]
B) \[2\]
C) \[1\]
D) \[0\]
Correct Answer: D
Solution :
\[3\frac{1}{12}-\left[ 1\frac{3}{4}+\left\{ 2\frac{1}{2}-\left( 1\frac{1}{2}-\frac{1}{3} \right) \right\} \right]\] \[=\frac{37}{12}-\left[ \frac{7}{4}+\frac{8}{6} \right]=\frac{37}{12}-\frac{37}{12}=0\]
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