question_answer

If the mercury in the barometer is replaced by water, what will be the resulting height of the water column? Density of water \[=1000\text{ }kgn{{r}^{3}}\]density of mercury \[=13600\text{ }kgn{{r}^{3}}\]

Answer:

\[{{h}_{mercury}}=76cm\]           \[{{d}_{mercury}}=13.6gc{{m}^{3}}\] \[{{g}_{mercury}}=g\]                    \[{{h}_{water}}=?\] \[{{d}_{water}}=1gc{{m}^{3}}\] \[{{g}_{water}}=g\] We know that \[P=hdg\] \[{{P}_{mercury}}={{P}_{water}}\] \[{{h}_{mercury}}\times {{d}_{mercury}}={{h}_{water}}\times {{d}_{water}}\] \[\Rightarrow \]\[{{h}_{water}}=\frac{76\times 13.6}{1}=1033.6\,cm=10.34\,m\] Therefore, the height of the water column is equal to 10.34 m.