question_answer

A person weighs 60 kg. The area under the foot of the person is \[\text{180 }c{{m}^{2}}\]. Find the pressure exerted on the ground by the person. (Take g \[=9.8\text{ }m/{{s}^{2}}\]).

Answer:

\[F=60\text{ }kg\text{ }wt=60\times 9.8\text{ }N\] \[=60\times \frac{98}{10}=6\times 98\,N\] Area under are foot                 \[(A)=180\text{ }c{{m}^{2}}=\frac{180}{1000}{{m}^{2}}\] \[\therefore \]\[P=\frac{F}{A}=\frac{6\times 98\times 10000}{180}Pa=\frac{98}{3}\times {{10}^{3}}Pa\] \[=32.6\times {{10}^{3}}Pa\]