A) \[0.098\text{ }N/{{m}^{2~}}\]
B) \[0.196\text{ }N/{{m}^{2}}\]
C) \[122.5\text{ }N/{{m}^{2~}}\]
D) \[245\text{ }N/{{m}^{2}}\]
Correct Answer: D
Solution :
Length of edge of a cube, \[a=2\text{ }cm=2\times {{10}^{2}}m\] Area of a surface of the cube, \[A={{a}^{2}}={{(2\times {{10}^{2}})}^{2}}=4\times {{10}^{4}}{{m}^{2}}\] Mass of the cube, \[m=10\text{ }g=0.01\text{ }kg\] Acceleration due to gravity, \[g=9.8\text{ }m/{{s}^{2}}\] Force exerted by the cube, \[F=mg\] \[=0.01\times 9.8=0.098\text{ }N\] Pressure is given by the relation, \[P=\frac{F}{A}=\frac{0.098}{4\times {{10}^{-4}}}=245\,N/{{M}^{2}}\] Therefore, the pressure exerted by the cube on the table is \[245\text{ }N/{{m}^{2}}.\] The correct answer is D.
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