A) \[1.03\text{ }\times \text{ }{{10}^{5\text{ }}}Pa\]
B) \[1.03\,\times \text{ 1}{{0}^{3}}\text{ }Pa\]
C) \[1.03\text{ }\times \text{ 1}{{0}^{4}}\text{ }Pa\]
D) \[1.03\text{ }\times \text{ }{{10}^{6}}\text{ }Pa\]
Correct Answer: A
Solution :
Atmospheric pressure = pressure of mercury column of height 76 cm. \[h=76\text{ }cm=0.76\text{ }m,\text{ }d=13600\text{ }kg{{m}^{3}},\] \[g=10\text{ }m{{s}^{2}}\] \[P=hdg=0.76\times 13600\times 10\text{ }Pa\] \[=1.03\times {{10}^{5}}Pa\] The correct answer is A.
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