A) \[0.\text{98 m}/{{\text{s}}^{\text{2}}}\]
B) \[\text{9}.\text{8 m}/{{\text{s}}^{\text{2}}}\]
C) \[0.\text{54 m}/{{\text{s}}^{\text{2}}}\]
D) \[\text{5}.\text{292 m}/{{\text{s}}^{\text{2}}}\]
Correct Answer: A
Solution :
force being applied even after the body has started moving \[={{\mu }_{s}}mg\] Force of kinetic friction in picture = ma So \[a=({{\mu }_{s}}-{{\mu }_{k}})g\] \[=0.1\times 9.8=0.98\]
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