A) \[\left( \frac{F}{M} \right)-a\]
B) \[a\]
C) \[-a\]
D) \[\left( \frac{F}{M} \right)\]
Correct Answer: A
Solution :
Here, the two masses are not tied by inextensible string. So, acceleration in different blocks will be different. Net force on block\[A=Ma\] Remaining force on \[B=F-Ma\] Acceleration of block\[B=\frac{F-Ma}{M}\]You need to login to perform this action.
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