A) 0.2
B) 0.4
C) 0.65
D) 0.75
Correct Answer: B
Solution :
\[\sin 30=\frac{h}{8}\] or \[h=4\,\,m\] On falling freely through a vertical height of\[4\,\,m\], velocity acquired by the body \[=\sqrt{2\times 10\times 4}=\sqrt{80}\] Now, \[{{v}^{2}}={{u}^{2}}-2as\] Friction retardation,\[a=\mu g\] \[\therefore \] \[80-16=2\mu g\times 8\] or \[\mu =0.4\]
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