A) \[\text{1}0\text{ g dyne c}{{\text{m}}^{\text{-2}}}\]
B) \[\text{2 dyne c}{{\text{m}}^{\text{-2}}}\]
C) \[\text{4}0\text{ g dyne c}{{\text{m}}^{\text{-2}}}\]
D) \[\text{45 g dyne c}{{\text{m}}^{\text{-2}}}\]
Correct Answer: D
Solution :
\[F=m(g+a)\] \[P=\frac{F}{A}=\frac{dAL(g+a)}{A}\] \[=1\times 15\times (g+2g)\]You need to login to perform this action.
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