A) 3 cm
B) 2 cm
C) 1cm
D) 0.5cm
Correct Answer: C
Solution :
Remaining velocity after penetrating \[3\,\,cm\] is half. So, remaining kinetic energy is one-fourth. So, the kinetic energy lost is three-fourth. In penetrating further, it will lose an additional energy of one-fourth. Applying work-energy theorem, \[\frac{3}{4}KE=F\times s\] and \[\frac{1}{4}KE=F\times s'\] \[\therefore \] \[s=\frac{s'}{3}\]You need to login to perform this action.
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