A) \[\frac{g}{2\sqrt{2}}\]
B) \[\frac{g}{\sqrt{2}}\]
C) \[\frac{3g}{2\sqrt{2}}\]
D) \[\frac{g}{2}\]
Correct Answer: A
Solution :
Retardation on an inclined plane \[=\mu g\cos \theta \] \[=0\cdot 5\times g\times \frac{1}{\sqrt{2}}=\frac{g}{2\sqrt{2}}\]
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