9th Class Science Force and laws of motion Question Bank Force and Laws of Motion

  • question_answer
    A weight of 290 N and another 200 N are suspended by a rope on either side of a frictionless pulley. The acceleration of each weight is

    A) \[\text{1}\text{.5 m}/{{\text{s}}^{\text{2}}}\]                   

    B)  \[\text{1}\text{.8 m}/{{\text{s}}^{\text{2}}}\]  

    C) \[\text{2}\text{.2 m}/{{\text{s}}^{\text{2}}}\]          

    D)        \[\text{2}\text{.5 m}/{{\text{s}}^{\text{2}}}\]

    Correct Answer: B

    Solution :

     In terms of weights, common acceleration\[a=\frac{{{w}_{1}}+{{w}_{2}}}{{{w}_{1}}+{{w}_{2}}}g\] Since all units are same, we do not care about the units of the calculated quantity, though there is hardly any problem in it.


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