A) Zero
B) 13 N
C) 3.3 M
D) 19.6 N
Correct Answer: B
Solution :
Referring figure\[,\] \[2g-{{T}_{1}}=2a\] ? (i) \[2g-{{T}_{1}}-{{T}_{1}}=2a\] ? (ii) and \[{{T}_{1}}-2g=2a\] ? (iii) Adding equations (i), (ii) and (iii), we get \[2g=6a\] From equation (i), \[\Rightarrow \] \[a=g/3\] \[2g-{{T}_{1}}=\frac{2g}{3}\] \[\Rightarrow \] \[{{T}_{1}}=\frac{4g}{3}=\mathbf{13}\,\,\mathbf{N}\]You need to login to perform this action.
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