|(i) 2||(ii) 11||(iii) 9|
A) Either (i) or (ii)
B) Either (ii) or (iii)
C) Either (i) or (ii) or (iii)
D) None of these
Correct Answer: A
Solution :N = 897324A64B For N divisible by 8, last three digits should be divisible by 8. For N divisible by 9, sum of digits should be divisible by 9. However, 64B is divisible by 8 when B equals 0 and 8. Now, if \[B=0,\]then A should be 2. And if \[B=8,\]then A should be 3. Then, \[(A+B)=2\]and 11.
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