8th Class Mathematics Factorisation Question Bank Factorisation

  • question_answer
    Simplify:- \[\frac{-14{{x}^{12}}y+8{{x}^{5}}z}{2{{x}^{2}}}\]

    A) \[{{x}^{3}}(-7{{x}^{7}}y+4z)\] 

    B)  \[{{x}^{2}}(7{{x}^{7}}y-4z)\]    

    C)  \[{{x}^{2}}(-7{{x}^{6}}y+2z)\]

    D)  \[{{x}^{3}}(-7{{x}^{7}}y+4z)\]

    Correct Answer: A

    Solution :

    \[\frac{-14{{x}^{12}}y+8{{x}^{5}}z}{2{{x}^{2}}}=\frac{2{{x}^{2}}(-7{{x}^{10}}y+4{{x}^{3}}z)}{2{{x}^{2}}}\] \[={{x}^{3}}(-7{{x}^{7}}y+4z)\]


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