A) \[4{{x}^{3}}{{y}^{2}}+2x{{y}^{3}}\]
B) \[4{{x}^{3}}y-2x{{y}^{3}}\]
C) \[-4{{x}^{2}}{{y}^{2}}+2x{{y}^{3}}\]
D) \[-4x{{y}^{2}}+2x{{y}^{3}}\]
Correct Answer: C
Solution :
\[\frac{32{{x}^{4}}{{y}^{3}}-16{{x}^{3}}{{y}^{4}}}{-8{{x}^{2}}y}=\frac{32{{x}^{4}}{{y}^{3}}}{-8{{x}^{2}}y}+\frac{16{{x}^{3}}{{y}^{4}}}{8{{x}^{2}}y}\] \[=-4{{x}^{2}}{{y}^{2}}+2x{{y}^{3}}\]
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