A) \[3(z+1)\,(z+2)\]
B) \[4(z+2)(z+3)\]
C) \[2(z+3)\,(z+1)\]
D) \[3(z+5)\,(z+5)\]
Correct Answer: A
Solution :
\[3{{z}^{2}}+9z+6=3({{z}^{2}}+3z+2)\] \[{{z}^{2}}+3z+2={{z}^{2}}+z+2z+2\] \[=z(z+1)+2(z+1)\] \[=(z+1)\,(z+2)\] \[\therefore \] \[3{{z}^{2}}+9z+6=3(z+1)\,(z+2)\]
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