A) \[{{(3m+4)}^{2}}=3{{m}^{2}}+6m+16\]
B) \[n(3n+2)=3{{n}^{2}}+2n\]
C) \[(x-2)\,(x-8)={{x}^{2}}-16\]
D) \[(p+2)\,(p+4)={{p}^{2}}+8\]
Correct Answer: B
Solution :
\[n(3n+2)=3{{n}^{2}}+2n\]
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