A) 4
B) 3
C) 2
D) 1
Correct Answer: A
Solution :
\[\,1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}\] principal quantum no. is 4 so it belongs to 4th period.
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